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0=12x^2-72x-84
We move all terms to the left:
0-(12x^2-72x-84)=0
We add all the numbers together, and all the variables
-(12x^2-72x-84)=0
We get rid of parentheses
-12x^2+72x+84=0
a = -12; b = 72; c = +84;
Δ = b2-4ac
Δ = 722-4·(-12)·84
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-96}{2*-12}=\frac{-168}{-24} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+96}{2*-12}=\frac{24}{-24} =-1 $
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